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What is the output of the following Java code?
public class array
{
public static void main(String args[])
{
int []arr = {1,2,3,4,5};
System.out.println(arr[5]);
}
}
{
public static void main(String args[])
{
int []arr = {1,2,3,4,5};
System.out.println(arr[5]);
}
}
- a)4
- b)5
- c)ArrayIndexOutOfBoundsException
- d)InavlidInputException
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
What is the output of the following Java code?public class array{ publ...
**Answer:**
The given Java code will throw an `ArrayIndexOutOfBoundsException` when executed.
**Explanation:**
In Java, arrays are zero-indexed, which means the first element of an array is accessed using the index 0, the second element with index 1, and so on.
In the given code, an array `arr` of size 5 is declared and initialized with the values `{1, 2, 3, 4, 5}`. However, when attempting to access `arr[5]`, we are trying to access the element at index 5, which is outside the valid range of the array.
The valid indices for this array are 0, 1, 2, 3, and 4. Since index 5 does not exist in the array, an `ArrayIndexOutOfBoundsException` is thrown at runtime.
The correct way to access the last element of the array would be to use `arr[arr.length - 1]`. This expression would evaluate to `arr[4]`, which is the value 5 in this case.
Therefore, the output of the given code will be:
```
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: Index 5 out of bounds for length 5
at array.main(array.java:7)
```
So, the correct answer is option **c) ArrayIndexOutOfBoundsException**.
The given Java code will throw an `ArrayIndexOutOfBoundsException` when executed.
**Explanation:**
In Java, arrays are zero-indexed, which means the first element of an array is accessed using the index 0, the second element with index 1, and so on.
In the given code, an array `arr` of size 5 is declared and initialized with the values `{1, 2, 3, 4, 5}`. However, when attempting to access `arr[5]`, we are trying to access the element at index 5, which is outside the valid range of the array.
The valid indices for this array are 0, 1, 2, 3, and 4. Since index 5 does not exist in the array, an `ArrayIndexOutOfBoundsException` is thrown at runtime.
The correct way to access the last element of the array would be to use `arr[arr.length - 1]`. This expression would evaluate to `arr[4]`, which is the value 5 in this case.
Therefore, the output of the given code will be:
```
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: Index 5 out of bounds for length 5
at array.main(array.java:7)
```
So, the correct answer is option **c) ArrayIndexOutOfBoundsException**.
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Community Answer
What is the output of the following Java code?public class array{ publ...
Trying to access an element beyond the limits of an array gives ArrayIndexOutOfBoundsException.
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